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miv72 [106K]
3 years ago
14

Mr. Rifkin had 240 digital and manual cameras. After donating 82 digital cameras and 26 manual cameras, he had 3 times as many d

igital cameras as manual cameras left. How many digital cameras did he have first?
Mathematics
1 answer:
Oliga [24]3 years ago
4 0
<span>He started with 184 digital cameras and 56 manual cameras

Work--> </span>d + m = 240   equation 1 (d-82) = 3(m-26)  equation 2d - 82 = 3m - 78d - 3m = 82 - 78d - 3m = 16         equation 2 simplified  d + m = 240d - 3m = 16         subtract equation 1 from equation 2---------------   -4m = -224      m = -224/-4      m = 56 d + m = 240d = 240-md = 240-56d = 184
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Pls help!!!!!!!!!!!!!!!!
Helga [31]

Answer:

m1=120

m2=120

m3=120

m4=60

m1=56

m2=56

m3=56

m4=124

6 0
3 years ago
PLS HELP ME WITH 1, 2, and 3!! (SHOW WORK!!) + LOTS OF POINTS!! *if u can do all 6, I will give brainliest and "thanks"
chubhunter [2.5K]
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6 0
3 years ago
−9 ≤ −3; Add 12 to both sides
almond37 [142]

Answer: -9+12=3     -3+12=9

Step-by-step explanation:

7 0
3 years ago
Communicative property
dezoksy [38]

The commutative property is a math rule that says that the order in which w multiply numbers does not change the product  

8*2=16 or 2*8=16

So,2*8=8*2


7 0
3 years ago
Suppose there exists a Hamming code of length 14 that corrects 2 errors. Assuming that the probability of a correct transmission
Mrac [35]

Answer:

0.8432

Step-by-step explanation:

The probability of a correct transmission of individual character = 0.9

Let's consider the three possible scenarios:

1) Probability of all 14 characters transmitted correctly = 0.9^14 = 0.2287

2)Probability of only one character being wrong: (0.9 ^ 13) * 0.1

This equals 0.02541    To account for the order at which the incorrect character is produced, lets consider the permutation: \frac{14!}{13!*1!}

This accounts for same objects or results being repeated, and is an integral part of permutation questions. The result is 14. Thus there are 14 ways for the probability of 0.02541 to occur. That means a total of 0.02541 * 14 probability. This equals 0.3559

3) Probability of both characters being wrong:

   Similar steps to (2). Probability = (0.9^12) * (0.1 ^ 2) =0.002824

   Number of ways this could occur: \frac{14!}{12!*2!} = 91

   Total probability for this event: 0.002842 * 91 = 0.2586

   The answer to our question is thus all these probabilities combined, which makes: 0.2287 + 0.3559 + 0.2586 = <u>0.8432</u>

5 0
3 years ago
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