1. X-7=-26 <br> 2. 11=x+ 5 <br> TYSM

The mean family income for a random sample of 600 suburban households in Loganville shows that a 95 percent confidence interval

Misha Larkins [42]

Answer:

$43100 \leq \mu \leq 59710$

And for this case we want to test the following hypothesis:

Null hypothesis: $\mu =42000$

Alternative hypothesis: $\mu \neq 42000$

For this case since the lower value of the confidence interval is higher than 42000 we have enough evidence to reject the null hypothesis at the 55 of significance and we can conclude that the true mean is significantly different from 42000

Step-by-step explanation:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is already calculated as:

$43100 \leq \mu \leq 59710$

And for this case we want to test the following hypothesis:

Null hypothesis: $\mu =42000$

Alternative hypothesis: $\mu \neq 42000$

For this case since the lower value of the confidence interval is higher than 42000 we have enough evidence to reject the null hypothesis at the 55 of significance and we can conclude that the true mean is significantly different from 42000

7 0

3 years ago

The value of y varies jointly with x and z. If y = 7 when z = 196 and x = 2, find the value of y when x = 3 and z = 336. I will

eimsori [14]

Answer:

18

Step-by-step explanation:

Given that:

y∞ xz

y=kxz. Where k is constant

When z=196 and x= 2 then y= 7

7=(196)(2)k

7=392k

k=1/56

There fore y=(1/56)xz

When x=3 and z =336

y=(1/56)xz

y=(1/56)(336)(3)

y=18

8 0

4 years ago

Help me figure this out please it’s due today i will name you brainliest!

kompoz [17]

Answer:

i know 4 is 1 i think

Step-by-step explanation:

7 0

3 years ago

There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one

diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

$P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02$

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01$

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05$

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C$

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0

4 years ago

In the diagram of circle C, what is the measure of 21?

kondaur [170]

Answer:

If I know what diagram you're referring to, which I believe I do, the answer is: ∠1=(1/2)[106°-36°]=35°

4 0

3 years ago

1. X-7=-26 2. 11=x+ 5 TYSM