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3 years ago

1. X-7=-26 2. 11=x+ 5 TYSM

Mathematics

2 answers:

laila [671]3 years ago

7 0

Answer:

[1] x = -19

[2] x = 6

Explanation:

x - 7 = -26

Add 7 to both sides

x - 7 + 7 = -26 + 7

Simplify

x = -19

11 = x + 5

Switch sides

x + 5 = 11

Subtract 5 from each side

x + 5 - 5 = 11 - 5

Simplify

x = 6

MariettaO [177]3 years ago

5 0

Answer: 1: X = − 19

2:x = 6

Step-by-step explanation:

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Answer:

$z=\frac{at-67}{45+a}$

Step-by-step explanation:

Step 1: Write out equation

a(t + z) = 45z + 67

Step 2: Distribute a

at + az = 45z + 67

Step 3: Subtract 67 on both sides

at + az - 67 = 45z

Step 4: Subtract az on both sides

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3 years ago

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Answer:

See graph

Step-by-step explanation:

The red graph is y = 2 sin x where the blue section represents one cycle where 0≤∅≤2π where ∅ is measured in radians.

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3 years ago

At the beginning of an experiment, the number of bacteria in a colony was counted at time t=O. The number of bacteria in the col

yan [13]

Answer:

1092

Step-by-step explanation:

We have been given that the number of bacteria in the colony t minutes after the initial count modeled by the function $B(t)=9(3)^t$ . We are asked to find the average rate of change in the number of bacteria over the first 6 minutes of the experiment.

We will use average rate of change formula to solve our given problem.

$\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}$

Upon substituting our given values, we will get:

$\text{Average rate of change}=\frac{b(6)-b(0)}{6-0}$

$\text{Average rate of change}=\frac{9(3)^6-9(3)^0}{6}$

$\text{Average rate of change}=\frac{9(729)-9(1)}{6}$

$\text{Average rate of change}=\frac{6561-9}{6}$

$\text{Average rate of change}=\frac{6552}{6}$

$\text{Average rate of change}=1092$

Therefore, the average rate of change in the number of bacteria is 1092 bacteria per minute.

8 0

3 years ago

Please help!

Zarrin [17]

They use 9 blocks each, a total of 18 blocks.

Bill: 4b + 2
Ron: 8b - 5

To look for the value of b; I assume that both used the same number of blocks.

4b + 2 = 8b - 5
4b - 8b = -5 -2
-4b = -7
-4b/-4 = -7/-4
b = 1.75

Bill: 4b + 2 where b = 1.75 ; then, 4(1.75) + 2 = 7 + 2 = 9
Ron: 8b - 5 where b = 1.75; then, 8(1.75) -5 = 14 - 5 = 9

5 0

3 years ago

Suppose you have 28 coins that are all dimes and quarters. The total value of the coins is $5.35. Write a system of equations th

Inessa [10]

Answer:

1) The system of equations that models this situation is given as follows

0.1·x + 0.25·y = 5.35...(1)

x + y = 28...(2)

2) The number of dimes = 11 dimes

The number of quarters = 17 quarters

Step-by-step explanation:

1) The given parameters are;

The numbers of quarters and dimes = 28

The total value of the coins = $5.25

Let x represent the number of dimes and y represent the number of quarters, and given that a dime = $0.1 and a quarter = $0.25, we have;

The system of equations that models this situation is given as follows

$0.1·x + $0.25·y = $5.35...(1)

x + y = 28...(2)

2) Making y the subject of both equations gives;

From equation (1), we have;

0.1·x + 0.25·y = 5.35

0.25·y = 5.35 - 0.1·x

y = 5.35/0.25 - 0.1/0.25·x = 21.4 - 0.4·x

y = 21.4 - 0.4·x

From equation (2), we have;

x + y = 28

y = 28 - x

Equating both equations to find the common solution, gives;

21.4 - 0.4·x = 28 - x

x - 0.4·x = 28 - 21.4

0.6·x = 6.6

x = 6.6/0.6 = 11

x = 11

The number of dimes = x = 11

y = 28 - x = 28 - 11 = 17

y = 17

The number of quarters = y = 17.

6 0

3 years ago