PLEASE HURRYY!!!!!!!!!!!!!
1 answer:
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Using the Pythagorean therom.
81 + b^{2} = 196
b^{2} = 115
b =
Hope this helps!
81 + b^{2} = 196
b^{2} = 115
b =
Hope this helps!
Answer:
Truck can safely carry <em>2310 pounds </em> of cargo.
Step-by-step explanation:
Given the safety limit of weight to cross the bridge safely is 4 tons.
1 ton is equal to 2000 pounds.
so, 4 tons are equal to 2000 4 = 8000 pounds
Now, given that
weight of empty truck and driver = 5690 pounds
To find:
Weight of cargo that the truck can safely carry ?
Solution:
Total weight of the truck is actually the combined weight of the empty truck, the drive and the cargo carried in it.
So, Total Weight allowed = 8000 pounds = 5690 pounds + Weight of Cargo
Weight of Cargo = 8000 - 5690 pounds
Weight of Cargo = <em>2310 pounds</em>
Truck can safely carry <em>2310 pounds </em> of cargo.
My work and the answer is shown up in the picture.
I used the substitution method to check my answers by using x and y into the two equations.
