Question

A dodecahedral die (one with 12 sides numbered from 1 to 12) is tossed once. Find the probability that the number on the upward face is divisible by 3. (Enter the probability as a fraction.)

Answer 1

Answer:

the probability is $\frac{1}{3}$

Step-by-step explanation:

there are 4 numbers on a 12 sided die that can be divided by 3: 3, 6, 9, and 12.

so the probability would be $\frac{4}{12}$, or $\frac{1}{3}$