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Yuliya22 [10]
3 years ago
8

Determine a scalar c so that the angle between a = i + cj and b = i + j is 45°.​

Mathematics
1 answer:
Marina CMI [18]3 years ago
6 0

Answer:

c=0

Step-by-step explanation:

ATQ a.b=|a||b|sin(45)

1+c=sqrt(1+c^2)*sqrt(2)*1/sqrt(2)

1+c=sqrt(1+c^2)

(1+c)^2=(1+c^2)

2c=0, c=0

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Which of the following is not equal to sin⁡(-230°)?
xenn [34]

From trigonometry we know that:

if sin(\theta)=sin(\alpha)

then, \theta=n\pi+(-1)^n\alpha (where n is an integer)

This can be rewritten in degrees as:

\theta=n(180^{\circ})+(-1)^n\alpha.............(Equation 1)

Now, in our case, \alpha=-230^{\circ}

Therefore, (Equation 1) can be written as:

\theta=n(180^{\circ})+(-1)^n(-230^{\circ})..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of \theta that match.

For n=2, (Equation 2) gives us: \theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}.

Thus, sin(230^{\circ})=sin(130^{\circ})

Now, we know that: -sin(-50^{\circ})=sin(50^{\circ})

Let n=-1, then:

\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}

Thus, sin(-230^{\circ})=-sin(-50^{\circ})

Likewise, sin(-230^{\circ})=sin(50^{\circ})

Only the last option sin(-50^{\circ}) will never match sin(-230^{\circ}) because no integral value of n will ever give \theta=-50^{\circ}

Thus the last option is the correct option.

3 0
3 years ago
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in the rectangular pyramid below , the length ,i , is 27cm , the width , w , is 30 2/3cm , and the height , h , is 9cm. What is
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Answer:

A. 2,484

Step-by-step explanation:

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Find the slope of the line (-4, -1) (1, 4)
timofeeve [1]

(y - yo) = m.(x - xo)

We have two points (-4, -1) and (1, 4)

(-1 - 4) = m.(-4 - 1)

(-5) = m.(-5)

m = (-5)/(-5)

m = 1

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7 0
3 years ago
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ANSWER THE 2 QUESTION IN 1 MINUTE AND YOU WILL BE THE BRAINLIEST! QUICK QUICK PLEASE!
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Answer:

1. 54

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1. 18 x 3 = 54

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3 years ago
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