It is given that there are 41 males and 48 females in the small school.
So, the number of ways a male student can be chosen from 41 males is
Likewise, the number of ways a female student can be chosen from 48 females is .
Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:
The option third "P(Male or Type B) < P(Male | Type B)" is correct because 0.575 < 0.76
<h3>What is probability?</h3>It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
P(Male or Type B) = (number of male + number of type B - number that are both)/total population
= 0.575
P(Male | Type B) = (number of male people inside the type B)/(number of Type B people)
= 38/(38 + 12)
= 0.76
0.575 < 0.76
P(Male or Type B) < P(Male | Type B)
Thus, the option third "P(Male or Type B) < P(Male | Type B)" is correct because 0.575 < 0.76
Learn more about the probability here:
#SPJ1