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2 years ago

5. Find the ratio of the price of coffee to that of tea, if coffee costs 48 per 100 gm and tea

Mathematics

1 answer:

Nimfa-mama [501]2 years ago

8 0

Answer:

COFEE COSTS - RS 48 PER 100 GRAM

COFEE COSTS - RS 48 PER 100 GRAMTEA COSTS - RS 280 PER KG

COFEE COSTS - RS 48 PER 100 GRAMTEA COSTS - RS 280 PER KGRATIO OF THE PRICE COFFEE TO THAT OF TEA - RS 48 PER 100 GRAM MEANS THAT 480 PER KG = 480/ 280 - 12:7

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Marilyn purchased a book that had a regular price of $19. She used a coupon that reduced the regular price by 15%. Sales tax for

Alika [10]

Answer:

2.80

Step-by-step explanation:

The discount is the regular price times the discount

discount = 19 *15%

discount = 2.85

The new price is the regular price minus the discount

new price = 19-2.85

=16.15

Now she has to pay the sales tax

tax = new price * tax rate

tax= 16.15 * 6.5%

= 16.15 *.065

=1.05

We add the tax to the new price to get the final price

final price = new price+tax

= 16.15 +1.05

=17.20

She pays with a 20 dollar bill

Change = payment - final price

=20.00 - 17.20

= 2.80

4 0

2 years ago

18. A I-10 number cube is rolled. What is the conditional probability that the number rolled is less than 6, given that the numb

Romashka-Z-Leto [24]

Answer:

30% Probability

Step-by-step explanation: 3/10=0.3

6 0

3 years ago

Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).

I am Lyosha [343]

Take the homogeneous part and find the roots to the characteristic equation:

$y''+4y=0\implies r^2+4=0\implies r=\pm2i$

This means the characteristic solution is $y_c=C_1\cos2x+C_2\sin2x$ .

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form $y_p=ax\cos2x+bx\sin2x$ . Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With $y_1=\cos2x$ and $y_2=\sin2x$ , you're looking for a particular solution of the form $y_p=u_1y_1+u_2y_2$ . The functions $u_i$ satisfy

$u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx$

where $W(y_1,y_2)$ is the Wronskian determinant of the two characteristic solutions.

$W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2$

So you have

$u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx$
$u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x$

$u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx$
$u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x$

So you end up with a solution

$u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x$

but since $\cos2x$ is already accounted for in the characteristic solution, the particular solution is then

$y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x$

so that the general solution is

$y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x$

7 0

3 years ago

The inverse of x y is: x y x y y x x y y x

serg [7]

Answer:

The inverse of xy is yx.

Step-by-step explanation:

Given: xy

We need to find the inverse of xy.

To find inverse of an expression, we need to replace the variable x by y and y by x.

Given xy.

Now replace x by y and y by x, we get

Therefore, the inverse of xy is yx.

Let me show you an example.

y = x - 2

To find the inverse function, replace x by y and y by x, we get

x = y - 2

It is an equation, to write the equation in terms of y, add 2 from both sides, we get

x + 2 = y -2 + 2

x + 2 = y

Therefore, y = x + 2

5 0

3 years ago

Who can help me?<br>please<br>Thank you

4vir4ik [10]

The sum of the interior triangles in a triangle is 180, so if we add all the angle measures together, we should get 180. Therefore, we can make an equation like this,

$110-2x+x+50+5x-40=180$