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3 years ago

The flow of water from a faucet can fill a

Mathematics

1 answer:

mash [69]3 years ago

8 0

Answer:

3/18 gallons/seconds, or 1/6 gallons/seconds

Step-by-step explanation:

We know that for every 3 gallons, the faucet fills that amount up in 18 seconds. Another way we can write that is "3 gallons for 18 seconds", or 3 gallons / 18 seconds.

Therefore, in terms of gallons to seconds, we can write this as 3 gallons/18 seconds.

One cool thing we can do with fractions is that if we multiply/divide the numerator by the same thing, the fraction is still the same amount, like if we divided by one. For example, if we multiply 1/10 by 10/10 = 1, we would get 10/100 = 1/10, changing the numbers but still keeping the fraction intact. We can apply this concept here to reduce the fraction.

Reducing the fraction means that we want to make the numerator and denominator as small as possible while still keeping them as integers. This means that, if possible, we should divide both the numerator and denominator by their greatest common factor (if it is greater than 1).

To find the greatest common factor, we can list factors and find the greatest one among them.

We have two numbers, 3 and 18.

The factors of 3 are 1 and 3 while the factors of 18 are 1, 2, 3, 6, 9, and 18. The greatest common number among these two is 3. Therefore, we can divide both these numbers by 3 to get

3/18 = 1/6 gallons/seconds as our answer

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6 (a + b) = 6a + 6b

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3 years ago

Use the given graph to determine the limit, if it exists. (4 points)

skelet666 [1.2K]

<h3>Answer: 3</h3>

Explanation:

Refer to the graph below. It should be similar to what your teacher gave you, based off the description.

Since we're approaching 3 from the right side, this means we'll be working with the horizontal line portion. We could start at something like x = 3.2 and move closer to 3 by getting to x = 3.1 then x = 3.01 then x = 3.001 and so on. We never actually get to 3 itself.

As x gets closer to 3 from this direction, the y values are approaching 3 since every point on this horizontal line has the same y coordinate. Technically the y value is already at 3, but it's the same idea.

In terms of notation, we can write $\displaystyle \lim_{x\to3^{+}}f(x) = 3$

The portion $x \to 3^{+}$ means we're approaching 3 from the positive side, aka the right hand side on the number line.

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2 years ago

An instructor in a college class recently gave an exam that was worth a total of 100 points. The instructor inadvertently made t

solniwko [45]

Answer:

B) Method 2 will increase the standard deviation of the students' scores.

Step-by-step explanation:

Given that an instructor in a college class recently gave an exam that was worth a total of 100 points.

The average score for his students was 43 and the standard deviation of the scores was 5 points.

And now he is considering two different strategies for rescaling the exam results of which:

Method 1 = Add 17 points to everyone's score.

Method 2 = Multiply everyone's score by 1.7 .

And we have to check what will be the impact of these methods on the standard deviation of the students' scores.

For this let us consider a simple example to understand this:

Firstly, Formula for calculating Standard Deviation = $\sqrt{\frac{\sum (X-Xbar)^{2}}{n-1}}$

Suppose,

X X - Xbar $(X - Xbar)^{2}$

3 3 - 6 = -3 -3 * -3 = 9

5 5 - 6 = -1 -1 * -1 = 1

10 10 - 6 = 4 4 * 4 = 16

Mean of above data, Xbar = $\frac{3+ 5+10}{3}$ = 6

Standard Deviation of data = $\sqrt{\frac{26}{3-1} }$ = 3.6055

Now let us suppose that we multiply each value of above data with 2 so the new data will be:

X X - Xbar $(X - Xbar)^{2}$

3*2 = 6 6 - 12 = -6 -6 * -6 = 36

5*2 = 10 10 - 12 = -2 -2 * -2 = 4

10*2 =20 20 - 12 = 8 8 * 8 = 64

Mean of new data, Xbar = $\frac{6+ 10+20}{3}$ = 12

Standard Deviation of new data = $\sqrt{\frac{104}{3-1} }$ = 7.2111

Hence, we see that when we multiply any value to the data the standard deviation will increase and in other words it will multiplied by that value which value we multiplied with each data value i.e. when we multiply each data value with 2 the standard deviation also get multiplied by as

3.6055 * 2 = 7.2111

Therefore option B is correct that Method 2 will increase the standard deviation of the students' scores.

And on the other hand Similarly by adding any constant to the data the Standard Deviation will remain same. Therefore Method 1 will have no impact on standard deviation of the students' scores.

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3 years ago