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Fed [463]
3 years ago
15

A middle school took all of its 6th grade students on a field trip to see a play at a theater that has 2100 seats. The students

left 987 seats vacant. What percentage of the seats in the theater were filled by the 6th graders on the trip?
Mathematics
1 answer:
GREYUIT [131]3 years ago
7 0

Answer:

2100 - 987 = 1113

1113/2100= 0.53

0.53 X 100 = 53%

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500\frac{1}{2}
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A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0
3 years ago
Hopefully, the final time I ask for help xD
gregori [183]

Answer:

y=-1/3x+15

Step-by-step explanation:

You only need to know the y-intercept which is 15, if you drew an imaginary line along the middle of the dots it would go through 15 and not 12.

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The product of two positive numbers is . what is the minimum value of their sum?
evablogger [386]
The answer is 29 value
7 0
3 years ago
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