Yes there is an error in this statement.
because x^2 = 25
so x = 5...this is one condition
Another condition is x = -5
(-5)^2 = 25 (this is also true)
Multiply all terms in the first equation by 2 and all terms in the second by 3.
You should obtain:
6x + 16y = 34
-6x + 27y = 9
------------------
43y =43, and so y = 1. Subbing 1 for y in the first eq'n, we get
3x + 8(1) = 17, or 3x = 9, or x = 3.
The solution is (3, 1).
To solve, we will follow the steps below:
3x+y=11 --------------------------(1)
5x-y=21 ------------------------------(2)
since y have the same coefficient, we can eliminate it directly by adding equation (1) and (2)
adding equation (1) and (2) will result;
8x =32
divide both-side of the equation by 8
x = 4
We move on to eliminate x and then solve for y
To eliminate x, we have to make sure the coefficient of the two equations are the same.
We can achieve this by multiplying through equation (1) by 5 and equation (2) by 3
The result will be;
15x + 5y = 55 ----------------------------(3)
15x - 3y =63 --------------------------------(4)
subtract equation (4) from equation(3)
8y = -8
divide both-side of the equation by 8
y = -1
Linear because the x are not repeating
AN EXAMPLE OF NON LINEAR”0,1,2,2,” AN EXAMPLE OF LINEAR”0,1,2,3” the non linear the x repeat so the answer is linear
