Question

The histogram below represents a data distribution with uniform class

Answer 1

Answer:

C. 5

Step-by-step explanation:

The given data can be presented as follows;

$\begin{array}{ccc}x&&y\\2&\leftrightarrow &1\\3&\leftrightarrow &4\\4&\leftrightarrow &6\\5&\leftrightarrow &7\\6&\leftrightarrow &6\\7&\leftrightarrow &3\\8&\leftrightarrow &2\\9&\leftrightarrow &1\\10&\leftrightarrow &1\end{array}$

We find the sum of the data points as follows;

n = 1 + 4 + 6 + 7 + 6 + 3 + 2 + 1 + 1 = 31

The median will be located in the (n + 1)/2 th data point

Therefore the median is the (31 + 1)/2 = 16th data point

The sum of the first three bars on the histogram = 11

The sum of the first four bars on the histogram = 18

Therefore, the 16th data point is located in the fourth bar which has x value of 5

The median is therefore, C. 5