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Luda [366]
3 years ago
6

Halp me plez I dont wanna fail ( MUST BE A EXPRESSION)

Mathematics
1 answer:
Scilla [17]3 years ago
4 0

Answer:

2x+15=33

Step-by-step explanation:

Let n be the number of days he has been doing sit ups, not counting the first day. Since he does 2 more sit-ups for each day, then the number of additional sit-ups is 2n.

Since he started doing  15 sit-ups on the first day, the total number of sit-ups

after x days would be 2n+15.

Since he did a total of 33 sit ups today, then 2n+15=33

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3 years ago
Simplify.<br> 3/3-n - n/n-3
Black_prince [1.1K]
\frac{3}{3-n}- \frac{n}{n-3}= \frac{3}{3-n}-(- \frac{n}{3-n})= \frac{3}{3-n}+\frac{n}{3-n}= \frac{3+n}{3-n}
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Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

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C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

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Total outcomes

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T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

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4 0
3 years ago
Multiply (2x^3 + 1)(5x^2 +4) and write your result in simplest form.
tatyana61 [14]
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