Answer:
-22,-6,-5,0,3,7,10
Step-by-step explanation:
It would be the highest negative integers in front, so going down, you'd reach 0. Then go up positive number 3,7,10.
Answer:
(9159 / 7 = 1308.429)
Step-by-step explanation:
Simply multiply the last digit by 2 and then subtract the product from the remaining digits.
If that difference is divisible by 7, then 9159 is divisible by 7.
The last digit in 9159 is 9 and the remaining digits are 915. Thus, the math to determine if 9159 is divisible by 7 using our alternate method is:
915 - (9 x 2) = 897
Since 897 is not divisible by 7, 9159 is also not divisible by 7.
Therefore, the answer to "Is 9159 Divisible By 7?" is no.
(9159 / 7 = 1308.429)
Y = f(3f - 4g + 3) +7g(3f - 4g + 3)
= 3f^2 - 4fg + 3f + 21fg - 28g^2 + 21g
= 3f^2 + 3f + 17fg + 21g - 28g^2
Answer:
The car was travelling at a speed of 60 miles per hour.
Step-by-step explanation:
Given:
Distance traveled = 330 miles
Time Period = ![5 \frac12\ hr](https://tex.z-dn.net/?f=5%20%5Cfrac12%5C%20hr)
we need to find the speed of the car .
Solution:
Time Period = ![5 \frac12\ hr](https://tex.z-dn.net/?f=5%20%5Cfrac12%5C%20hr)
Now we can say that;
![\frac12\ hr =0.5\ hr](https://tex.z-dn.net/?f=%5Cfrac12%5C%20hr%20%3D0.5%5C%20hr)
So Time period = ![5+0.5 =5.5\ hr](https://tex.z-dn.net/?f=5%2B0.5%20%3D5.5%5C%20hr)
Now we know that;
Distance traveled
is equal to Speed
multiplied by Time Period
.
framing in equation form we get;
![d=rt\\\\330 =r\times 5.5](https://tex.z-dn.net/?f=d%3Drt%5C%5C%5C%5C330%20%3Dr%5Ctimes%205.5)
Dividing both side by 5.5 we get;
![\frac{330}{5.5}=\frac{5.5r}{5.5}\\\\r = 60\ mi/hr](https://tex.z-dn.net/?f=%5Cfrac%7B330%7D%7B5.5%7D%3D%5Cfrac%7B5.5r%7D%7B5.5%7D%5C%5C%5C%5Cr%20%3D%2060%5C%20mi%2Fhr)
Hence The car was travelling at a speed of 60 miles per hour.