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3 years ago

Please help me! I need it. I will give branliest

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

5 0

A is 69000 I hope you do good on your test/homework

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andre is writing a paper for science class he can type 30 words per minute what is the ratio of words to minutes

soldi70 [24.7K]

Answer:

30words

30/ 60 = 1/2

The ratio is 1:2

Thank you and please rate me as brainliest as it will help me to level up

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3 years ago

(Pls I need Help) Each figure shown is a constant enlargement of the previous figure. Which rule below could be used to determin

vova2212 [387]

Answer:

I'm here for that the guy who has answer this is correct

Step-by-step explanation:

I had the same answer in got it right

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2 years ago

Mary is making a pinata that has a ball-like shape. The pinata has a surface area of 40 feet. Use the formula for the surface ar

Neko [114]

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3 years ago

The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation

MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

$\bar x = \frac{\sum_{i=1}^n X_i}{n}$

And the population mean is given by:

$\mu= \frac{\sum_{i=1}^n X_i}{N}$

The population variance is defined by:

$\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}$

And the sample variance is defined as:

$s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}$

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is $\sigma=2$ then the variance would be $\sigma^2 = 4$ and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is $\sigma=0.1$ then the variance would be $\sigma^2 = 0.01$ and as we can see is lower than the standard deviation