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iragen [17]
3 years ago
11

Find the equation of The line perpendicular to Y= -2+3/5X passing through the points (3, -4)

Mathematics
1 answer:
Alex777 [14]3 years ago
6 0

Answer:

y = -1\frac{2}{3} + 1

Step-by-step explanation:

The line (a) passing through point (3, -4) is perpendicular to line (b) whose equation is; y = -2 + \frac{3}{5}x

The slope of line (b) = \frac{3}{5}

For perpendicular lines, the product of their slopes = -1

So line (a) has a slope of: -1 ÷ \frac{3}{5} = -\frac{5}{3}

Taking another point (x,y) on line (a);

Slope = change in y ÷ change in x

\frac{y - -4}{x - 3} = -\frac{5}{3}

y + 4 = \frac{5}{3}(x - 3)

y = -\frac{5}{3}x + 5 - 4

y = -\frac{5}{3}x + 1

Finally,

y = -1\frac{2}{3} + 1

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