Question

Find the equation of The line perpendicular to Y= -2+3/5X passing through the points (3, -4)

Answer 1

Answer:

y = -1$\frac{2}{3}$ + 1

Step-by-step explanation:

The line (a) passing through point (3, -4) is perpendicular to line (b) whose equation is; y = -2 + $\frac{3}{5}$x

The slope of line (b) = $\frac{3}{5}$

For perpendicular lines, the product of their slopes = -1

So line (a) has a slope of: -1 ÷ $\frac{3}{5}$ = -$\frac{5}{3}$

Taking another point (x,y) on line (a);

Slope = change in y ÷ change in x

$\frac{y - -4}{x - 3}$ = -$\frac{5}{3}$

y + 4 = $\frac{5}{3}$(x - 3)

y = -$\frac{5}{3}$x + 5 - 4

y = -$\frac{5}{3}$x + 1

Finally,

y = -1$\frac{2}{3}$ + 1