Answer:
Option B
Step-by-step explanation:
From the picture attached,
In ΔABC,
m∠B = m∠C = 75° [Isosceles triangles]
By applying triangle sum theorem,
m∠A + m∠B + mC = 180°
m∠A + 75° + 75° = 180°
m∠A = 180° - 150°
m∠A = 30°
In triangle PQR,
m∠P = m∠Q [Isosceles triangle]
By applying triangle sum theorem,
m∠P + m∠Q + m∠R = 180°
2(m∠P) + 30° = 180°
m∠P = 75°
m∠P = m∠Q = 75°
In ΔABC and ΔRPQ,
m∠B ≅ m∠Q [Given]
m∠C ≅ m∠R [Given]
Therefore, by AA property of similarity of two triangles, both the triangles will be similar.
ΔABC ~ ΔRPQ
Option B will be the answer.
