Let x = amount of 45% antifreezeLet y = amount of 70% antifreeze EQUATION 1: x + y = 150 (total of 150 gallons mixed) EQUATION 2: .45x + .75y = .55(x + y) Simplify and solve the system of equations Multiply second equation by 100 on both sides to remove the decimals 45x + 75y = 55(x + y) Combine like terms 45x + 75y = 55x + 55y 45x - 55x + 75y - 55y = 0 -10x + 20y = 0 Now we have the following system of equations: x + y = 150 -10x + 20y = 0 Multiply the first equation by -10 to get opposite coefficients for x; add the equations to eliminate x 10x + 10y = 1500 -10x + 20y = 0 ------------------------------ 30y = 1500 Solve for y 30y = 1500 y = 50 Since the total mixed gallons is 150, x = 150 - 50 = 100 So we need 100 gallons of the 45% antifreeze and 50 gallons of the 70% antifreeze
Answer:
A (x+3)−1=8open paren x plus 3 close paren minus 1 is equal to 8
C 2(x+3)=182 times open paren x plus 3 close paren is equal to 18
E 2x=122 x is equal to 12
Step-by-step explanation:
Given:
2(x+3) − 2 = 16
2x + 6 - 2 = 16
2x = 16 - 6 + 2
2x = 12
x = 12/2
x = 6
A. (x+3)−1=8
x + 3 - 1 = 8
x = 8 - 3 + 1
x = 6
B (x+3)−2=8
x + 3 - 2 = 8
x = 8 - 3 + 2
x = 7
C 2(x+3)=18
2x + 6 = 18
2x = 18 - 6
2x = 12
x = 12/2
x = 6
D x+3=9x
3 = 9x - x
3 = 8x
x = 3/8
E 2x=12
x = 12/2
x = 6
F 2x=15
x = 15/2
x = 7 1/2
-3^-3=-1/3^3=-1/27
Indeed.
The top one is correct …..correct is correct
The answer is 0 bcuz it will be 5n=0
Give me a thanks if it helps!!
