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matrenka [14]
3 years ago
12

P v ~Q => QConstruct truth tablePlease need it ASAP​

Mathematics
1 answer:
Kipish [7]3 years ago
3 0

<em>p</em>   …   <em>q</em>   …   ¬<em>q</em>   …   <em>p</em> ∨ ¬<em>q</em>   …   (<em>p</em> ∨ ¬<em>q</em>) ⇒ <em>q</em>

T   …   T   …    F   …        T        …          T

T   …   F   …    T   …        T        …          F

F   …   T   …    F   …        F        …          T

F   …   F   …    T   …        T        …          F

Start with the first two columns, taking every possible pair of True/False for <em>p</em> and <em>q</em>.

¬<em>q</em> is just the negation of <em>q</em>, so True becomes False and False becomes True.

<em>p</em> ∨ <em>q</em> is the logical disjunction, or logical "or". It's True if either <em>p</em> or <em>q</em> is True, and False otherwise. So <em>p</em> ∨ ¬<em>q</em> is True only if either <em>p</em> or ¬<em>q</em> is True.

<em>p</em> ⇒ <em>q</em> is the logical implication. It's True only when both <em>p</em> and <em>q</em> are True, or when <em>p</em> is False. So (<em>p</em> ∨ ¬<em>q</em>) ⇒ <em>q</em> is True when both <em>p</em> ∨ ¬<em>q</em> and <em>q</em> are True, or when <em>p</em> ∨ ¬<em>q</em> is False.

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20%20%20%5Cdiv%202%20%2B%202%20%5Cdiv%20%20%5Csqrt%7B2%20%7D%20" id="TexForm
NeX [460]

Answer:

\frac{3\sqrt{2} }{2}

Step-by-step explanation:

Given

\frac{\sqrt{2} }{2} + \frac{2}{\sqrt{2} } ← rationalise the denominator by multiplying by \frac{\sqrt{2} }{\sqrt{2} }

= \frac{\sqrt{2} }{2} + ( \frac{2}{\sqrt{2} } × \frac{\sqrt{2} }{\sqrt{2} } )

= \frac{\sqrt{2} }{2} + \frac{2\sqrt{2} }{2}

= \frac{3\sqrt{2} }{2}

5 0
3 years ago
Which number is a rational number???
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Using the formula D= r•t where D equals distance traveled, r equals the average rate of speed and t equals the time traveled, ch
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Here is how to do the question,

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Hope that helps!!!!

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3 years ago
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