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Daniel [21]
3 years ago
8

A rock is thrown upward at a speed of 69 mph when the rock reaches its peak how fast is it going and what is the magnitude and a

cceleration
Mathematics
1 answer:
aleksandrvk [35]3 years ago
6 0
At it's peak the rock is going 0mph the acceleration is .0000038 m/s^2 if on earth
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lara has 90 mild peppers and 36 hot peppers. she is putting them into baskets so that each basket has the same number of mild pe
Mariulka [41]

Answer:

Up to 36

Step-by-step explanation:

If she puts one pepper hot pepper in every basket she can make a total of 36 baskets

8 0
3 years ago
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
Komok [63]

Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=60−77 /12

Z=−1.4167

Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

b. In this case For X = 75, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=75−77 /12

Z=−0.1667

Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is obtained as follows:

P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

=0.4338−0.0783

=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

Z=  X−μ /σ

Z=90−77 /12

Z​=1.0833

UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

=1−0.8599

=0.1401

​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

6 0
3 years ago
Rewrite 1/5and1/2 as a unit rate
denpristay [2]

Answer:

1/2 = 0.5

1/5 = 0.2

Step-by-step explanation:

Hope this helps!!!

4 0
3 years ago
Simplify -8(n+5) -3n
pshichka [43]
-8n-25-3n then you would need too add like terms and it'd be -11n-25 
8 0
3 years ago
Read 2 more answers
5 3/8 c =___ fl oz
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5 3/8 c =_43__ fl oz

and

65 in =_5 5/12 ___ ft



3 0
3 years ago
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