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Olegator [25]
3 years ago
14

Select all the numbers that are irrational

Mathematics
1 answer:
NARA [144]3 years ago
6 0
<h3>2 Answers:</h3>

A)  -\sqrt{5}

D)  \pi

===========================================

Explanation:

Choices B and C are rational because we can simplify them to form a fraction of integers.

-\sqrt{49} = -7 = -\frac{7}{1}

\sqrt{0} = 0 = \frac{0}{1}

Any rational number is of the form P/Q where P,Q are integers and Q is nonzero.

So we can rule out choices B and C.

---------------

Choice A on the other hand cannot be written as a fraction of integers. The 5 isn't a perfect square, which makes -\sqrt{5} irrational.

The same can be said about \pi which is roughly equal to 3.14; the decimal digits go on forever without a known pattern.

Choice A and choice D are the two answers.

----------------

If we know the pattern of the decimal digits, then we can turn the decimal number into a fraction of integers

The number -0.777, where the 7s go on forever, converts to the fraction -7/9

That means we rule out choice E.

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Applying the triangle proportionality theorem, the missing segment length is: 3.

<h3>What is the Triangle Proportionality Theorem?</h3>

The triangle proportionality theorem states that if a line that is parallel to a third side intersects the other two sides of a triangle, it divides them proportionally.

Let x represent the given segment length. Using the triangle proportionality theorem, we would have:

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Solve these equations using elimination not substitution? 8x + 3y = 13 3x + 2y = 11 15 Points!
tia_tia [17]

Answer:

x = -1, y = 7

Step-by-step explanation:

8x + 3y = 13

3x + 2y = 11

Multiply the first equation by -2 and the second equation by 3. Then add them.

     -16x - 6y = -26

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--------------------------

       -7x         = 7

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Now substitute x = -1 in the first original equation and solve for y.

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8 0
3 years ago
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