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2 years ago

What is the meaning of life, the universe, and everything?

Mathematics

2 answers:

disa [49]2 years ago

6 0

Answer:

meaning of life is life

Svetradugi [14.3K]2 years ago

3 0

Answer:

a common name for the off-topic section of an Internet forum and the phrase is invoked in similar ways to mean. when asked about the meaning of life, will answer "42". Several online calculators are also programmed with the Question.

<h2>Step-by-step explanation: 42</h2>

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Select a number that can complete the equation so that it has no solution. 6(x-7/6)=6x+__

BlackZzzverrR [31]

$6(x - \frac{7}{6} ) = 6 x - 7 \\ 6x - 7 = 6x + ( - 7)$
The answer is the third option, -7.

Hope this helps.

7 0

2 years ago

Help please !! 20 points

Readme [11.4K]

For the table 0.2 would be (1/5) 0.5 would be (1/2). And 0.7 would be (7/10).

For number 2 I would say the denominator changed each time

8 0

3 years ago

What is the initial value, and what does it represent?

inn [45]

Answer:

A. The initial value is 100; it represents money left over from last year's fundraiser

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Somebody help on 39 and 40 !

BlackZzzverrR [31]

39 is A
40 is D
And that is my answer

3 0

2 years ago

Read 2 more answers

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

2 years ago