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Mrac [35]
2 years ago
11

Brayden has 342 marbles in bags. If there are 9 marbles in each bag, how many bags of marbles does Brayden have If Brayden gives

away 15 of his bags of marbles, how many bags does he have left
Mathematics
1 answer:
Firlakuza [10]2 years ago
8 0
Brayden has 38 bags.
After giving away 15 bags of marbles, Brayden is left with 23 bags.

To find out how many bags he has we do 342 divided by 9 which is 38.

To find out how many marbles are in 15 bags we do 15 x 9 which is 135.
We then do 342 - 135 to find out how many marbles he has left which is 207 and divide 207 by 9 to convert that into bags, which is 23.
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Answer:

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Evaluate the function.
Natali5045456 [20]
As you may already be familiar, these functions f(x) and g(x) are piecewise. They consist of multiple functions with different domains.

1. For #1, the given input is f(0). Since 0≤1, you should use the first equation to solve. f(0)=3(0)-1 ➞ f(0)=-1
2. Continue to evaluate the given input for the domains given. 1≤1, therefore f(1)=3(1)-1➞f(1)=2
3. 5>1, therefore f(5)=1-2(5)➞f(5)=-9
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Hope this helps! Good luck!
5 0
3 years ago
Read 2 more answers
x^2-y=7 and y-5x=-11 The system of equations above has two solutions. The solution in Quadrant 1 is (A,B) and the solution in Qu
dimaraw [331]

By solving the system of equations, we can see that the solutions are:

(A, B) = (4, 9)

(C, D) = (1, -6).

<h3>How to solve the system of equations?</h3>

Here we have the following system of equations:

x^2 - y = 7

y - 5x = -11

If we isolate the variable y in both equations, we get:

y = x^2 - 7

y = -11 + 5x

Now we can equate these two to get:

x^2 - 7 = -11 + 5x

now we have a quadratic equation, this can be rewritten as:

x^2 - 7 + 11 - 5x = 0

x^2 - 5x + 4 = 0

Using the quadratic formula, we will see that the solutions are:

x = \frac{5 \pm \sqrt{(-5)^2 - 4*1*(4)} }{2*1}

Solving that we get:

x = \frac{5 \pm \sqrt{(9} }{2} \\\\x = \frac{5 \pm 3}{2}

So the two solutions for x are:

x = (5 + 3)/2 = 4

x = (5 - 3)/2 = 1

Evaluating the second equation in these x-values we get:

y = -11 + 5*4 = -11 + 20 = 9

y = -11 + 5*1 = -6

Then we have the coordinate pairs: (4, 9) (on the first quadrant) and (1, -6) on the fourth quadrant.

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1 year ago
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Anarel [89]

Answer:

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3 years ago
A certain radioactive material decays in such a way that the mass in kilograms remaining after t years is given by the function
Angelina_Jolie [31]

The mass of radioactive material remaining after 50 years would be 48.79 kilograms

<h3>How to determine the amount</h3>

It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.

Given the radioactive decay formula as

m(t)=120e−0.018t

Where

t= 50 years

m(t) is the remaining amount

Substitute the value of t

m(t) = 120e^-^0^.^0^1^8^(^5^0^)

m(t) = 120e^-^0^.^9

Find the exponential value

m(t) = 48.788399

m(t) = 48.79 kilograms to 2 decimal places

Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms

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