Answer:
A
Step-by-step explanation:
<h3>Numerator</h3>
(3x)(3x) = 9x^2
√9x^2 = 3x
Numerator = 3x
<h3>Denominator</h3>
√18y^2 = √18 · √y^2
√18 = 3√2
√y^2 = y
3√2y
Denominator = 3√2y
Now we need to rationalize the denominator, and get rid of the square root on the bottom
* 
= 
= 
( –6m^7 + 20m^6<span>) ÷ 2m^4 = ???
as you know
</span> –6m^7 + 20m^6 = 2m^4 (-3m^3 + 10m^2)
[2m^4 (-3m^3 + 10m^2) ] / 2m^4 (2m^4 is canceled out)
= -3m^3 + 10m^2
answer is B. –3m^3 + 10m^2
Answer:
The smaller number is 4
Step-by-step explanation:
Larger number = x
Smaller number = y
Write 2 equations
y + 6 = x
2x = 5y
Substitute x in the first equation to the second equation
2(y + 6) = 5y
Multiply 2(y + 6)
2y + 12 = 5y
Subtract 2y from both sides of the equation
12 = 3y
Divide both sides of the equation by 3
y = 4
x = y + 6 = 4 + 6 = 10
The smaller number is 4
Hope this helps :)
Answer:
h(x)
Step-by-step explanation:
to solve for an inverse, you swap the x and the y and then solve for y
f(x) = 4x^3-8
y = 4x^3 - 8
x = 4y^3 - 8 swap the x and y
now solve for y:
x + 8 = 4y^3
(x + 8)/4 = y^3
1/4x + 8/4 = y^3
1/4x + 2 = y^3
y = ![\sqrt[3]{1/4x + 2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1%2F4x%20%2B%202%7D)
