What set of reflections and rotations would carry rectangle ABCD Rotate 180°, reflect over the y-axis, reflect over the line y=x
1 answer:
You might be interested in
11x + y = 4
<u>x | y</u>
0 | 4
| 0
<em>plot the y-intercept (0, 4) and the x-intercept (, 0) </em>
or
11x + y = 4
<u>-11x </u> <u>-11x </u>
y = -11x + 4 ⇒ m = , b = 4
<em>plot at point the y-intercept "b = 4" (0,4). plot the next point using the slope "m = " from point (0,4), count down 11 and to the right 1 (1,-7).</em>
Using intercepts would not provide an accurate graph because you have to estimte where (, 0) is, so it is best to use slope-intercept form.
***********************************************************************************************************
x + y = -2
<u>x | y</u>
0 | -2
-2 | 0
<em>plot the y-intercept (0, -2) and the x-intercept (-2, 0)</em>
or
x + y = -2
<u>-x </u> <u> -x </u>
y = -x - 2 ⇒ m = , b = -2
<em>plot at point the y-intercept "b = -2" (0,-2). plot the next point using the slope "m = " from point (0,-2), count down 1 and to the right 1 (1,-3).</em>
Both methods are easy to use so either can be used.
**********************************************************************************************************
x - 2y = 18
<u>x | y</u>
0 | -9
18 | 0
<em>plot the y-intercept (0, -9) and the x-intercept (18, 0)</em>
or
x - 2y = 18
<u>-x </u> <u> -x </u>
-2y = -x + 18
y = - 9
<em>plot at point the y-intercept "b = -9" (0,-9). plot the next point using the slope "m = " from point (0,-9), count up 1 and to the right 2 (2,-8).</em>
Using intercepts will make a large graph since you have to plot (18,0) so it is best to use the slope-intercept form.
