All categories

3 years ago

Please help me I will give you the brain thing and extra points (image below) 1/5

Mathematics

2 answers:

tresset_1 [31]3 years ago

8 0

Answer:

Step-by-step explanation:

A is the only answer with a correct slope

well you dont need to know anything about special triangles

You just need to know rise over run

for example when you wake up, do you run or rise first, rise first.

so Q is the only one rising so it should be the numerator, the others are putting run first.

nignag [31]3 years ago

4 0

The answer is A hope this helps

You might be interested in

Emma works 30 hours per week and earns a monthly salary of $2370. (Assume there are 4 weeks in a month). Belle earns $4.20 every

andreev551 [17]

Answer:

emma earns more per hour and per week too i know this b/c i did it already

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is -r-10r combine like terms

goldfiish [28.3K]

-r -10r

fractor out -r

-r(1 +10)

-r(11)

-11r

Answr: -11r

3 0

3 years ago

Read 2 more answers

How many seconds in 35 minutes

topjm [15]

All you have to do is multipy the amount of minutes by 60 seconds because there are 60 seconds in every minute.
35 minutes x 60 seconds
2100 secods

3 0

3 years ago

Read 2 more answers

What is the area of this figure

kobusy [5.1K]

I think 20 hope that helps

5 0

4 years ago

Read 2 more answers

Can someone help me solve this differentiation/tangent problem?

nirvana33 [79]

A)

$\bf g'(x)=\stackrel{product~rule}{2x\cdot f(x)+x^2\cdot f'(x)}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
g'(5)=2(5)\cdot f(5)+(5)^2\cdot f'(5)\implies g'(5)=50+500\\\\\\ g'(5)=550\\\\
-------------------------------\\\\
g(5)=(5)^2f(5)\implies g(5)=125
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}
\begin{cases}
x=5\\
y=125\\
\stackrel{m}{g'(5)}=550
\end{cases}\implies y-125=550(x-5)
\\\\\\
y-125=550x-2750\implies y=550x+400$

b)

$\bf h'(x)=\stackrel{quotient~rule}{\cfrac{f'(x)(x-6)~~-~~f(x)\cdot 1}{(x-6)^2}}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
h'(5)=\cfrac{f'(5)(5-6)~~-~~f(5)\cdot 1}{(5-6)^2}
\\\\\\
h'(5)=\cfrac{5(-1)-5}{(-1)^2}\implies h'(5)=-10\\\\
-------------------------------\\\\$

$\bf h(5)=\cfrac{f(5)}{5-6}\implies h(5)=\cfrac{5}{-1}\implies h(5)=-5
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\quad 
\begin{cases}
x=5\\
y=-5\\
\stackrel{m}{-10}
\end{cases}\implies y-(-5)=-10(x-5)
\\\\\\
y+5=-10x+50\implies y=-10x+45$

3 0

4 years ago