Question

Express the complex number 6 in complex trigonometric form.

Answer 1

Hello,

6=6*(cos 0 +i *sin 0)

Answer 2

Answer:

6(cos 0° + sin 0° . i)

Step-by-step explanation:

The trigonometric form formula is a combination of the following formulas:

Binomic: a + bi

Polar: rα

Giving as a result the formula: r (cos α + sin α · i)

Where,

r = module

α = angle

In the given case, the complex number is 6, where

Binomic form: 6 + 0i

Where a = 6 and b = 0

We must calculate the module (r) and the angle (α).

$r=\sqrt{a^{2} +b^{2}} =\sqrt{6^{2} +0^{2}}=\sqrt{36}=6$

α = $tan^{-1}(0)$ = 0°

Since r=6 and α=0°, then the trigonometric form is

r(cos α + sin α · i)  = 6(cos 0° + sin 0° . i)

Hope this helps!