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elena-14-01-66 [18.8K]
3 years ago
15

Solve for x and y in the figure below:

Mathematics
1 answer:
FromTheMoon [43]3 years ago
6 0

Hey do you have the rest of the answer for the mid unit ?

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Figure ABCD is a kite
Mars2501 [29]
The kite is symmetric about line segment BD.
Therefore
AB = BC
3x + 1 = 22
3x = 22 - 1 = 21
x = 21/3 = 7

Similarly,
AD = CD by symmetry
Therefore
4x = CD
4*7 = CD
28 = CD, the required line segment

Answer: 28
4 0
3 years ago
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Plss help it’s a test I’ll give 10 points
vodomira [7]

Answer:

Its the 3rd answer :)

<em>x = 26.94</em>

Step-by-step explanation:

<h2><em>This is because 25.5 + 1.44 = 26.94 :) (inverse operations ;))</em></h2>

<em />

4 0
3 years ago
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What fraction is 4mm of 10cm
Sever21 [200]
Answer is going to be: 4/100
8 0
2 years ago
(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
3 years ago
What is the probability that a coin will be flipped 4 times and the result will be HTHT?
zepelin [54]
I think the answer is 1/16 because there is only one way that HTHT can fall out of 16 possible outcomes. That's what I think. Hope this helps!
5 0
3 years ago
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