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3 years ago

Write an equation to describe the relationship in each table

Mathematics

1 answer:

Yuri [45]3 years ago

5 0

Answer:

1: $y=x+6$

2 $y=\frac{1}{2}x$

Step-by-step explanation:

If I helped, a brainliest answer would be greatly appreciated!

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Which of the following situations are equal to 30%? Select all that apply A) 27 out of 90 B) 12 out of 36 C) 50 out of 80 D) 9 o

siniylev [52]

Answer:

27 out of 90; 9 out of 30

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3 years ago

A student factors 3x2 – 12 to the following.

Nesterboy [21]

Answer: The Expression is Equivalent, However, NOT completely factored.

Step-by-step explanation:

3x^2 - 12

Following:

3 ( x^2 - 4 )

Factor:

3x^2 - 12

Factor Out Common Term 3:

3 ( x^2 - 4 ) = 3 (x^2 - 4 )

Factor:

x^2 - 4

( x + 2 ) ( x - 2 )

Answer:

3 ( x + 2) ( x - 2)

Hence, The Expression is Equivalent, However, Wasn't Completely Factored.

Hope that helps!

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3 years ago

Read 2 more answers

A group of friends wants to go to the amusement park. They have no more than $150

algol [13]

Answer: 17.75p + 8 ≤ 150 OR p ≤ 8

Step-by-step explanation:

7 0

2 years ago

suppose you toss a coin 100 times and get 60 heads and 40 Tails based on these results what is the probability that the next fli

8_murik_8 [283]

It is stil half becuase the real probability doesnt change

4 0

3 years ago

Salaries of 49 college graduates who took a statistics course in college have a mean, x overbar, of $ 65 comma 300. Assuming a

Molodets [167]

Answer: $60,540< \mu$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}-z^*\dfrac{\sigma}{\sqrt{n}}< \mu$

, where $\sigma$ = Population standard deviation.

n= sample size

$\overline{x}$ = Sample mean

z* = Critical z-value .

Given : $\sigma=\$17,000$

n= 49

$\overline{x}= \$65,300$

Two-tailed critical value for 95% confidence interval = $z^*=1.960$

Then, the 95% confidence interval would be :-

$65,300-(1.96)\dfrac{17000}{\sqrt{49}}< \mu$

$=65,300-(1.96)\dfrac{17000}{7}< \mu$

$=65,300-4760< \mu$

$=60,540< \mu$

Hence, the 95% confidence interval for estimating the population mean $(\mu)$ :

$60,540< \mu$

7 0

3 years ago