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valentina_108 [34]
2 years ago
9

7(r-5)-3=r+34 what is the answer

Mathematics
1 answer:
geniusboy [140]2 years ago
4 0
7(r-5)-3=r+34
7r-35-3=r+34
7r-32=r+34
7r-r=34+32
6r=4
6r divide by 6= 4 out if 6
Reduce it to its simplest form so 4 divide by 2 and 6 divide by 2 and your answer will be 2 out of 3


Hope this helps!!!
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Answer: Choice A.)   88.2 < μ < 93.0

=============================================================

Explanation:

We have this given info:

  • n = 92 = sample size
  • xbar = 90.6 = sample mean
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Because n > 30 and because we know sigma, this allows us to use the Z distribution (aka standard normal distribution).

At 99% confidence, the z critical value is roughly z = 2.576; use a reference sheet, table, or calculator to determine this.

The lower bound of the confidence interval (L) is roughly

L = xbar - z*sigma/sqrt(n)

L = 90.6 - 2.576*8.9/sqrt(92)

L = 88.209757568781

L = 88.2

The upper bound (U) of this confidence interval is roughly

U = xbar + z*sigma/sqrt(n)

U = 90.6 + 2.576*8.9/sqrt(92)

U = 92.990242431219

U = 93.0

Therefore, the confidence interval in the format (L, U) is approximately (88.2, 93.0)

When converted to L < μ < U format, then we get approximately 88.2 < μ < 93.0 which shows that the final answer is choice A.

We're 99% confident that the population mean mu is somewhere between 88.2 and 93.0

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3 years ago
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Answer: The widths of Kyle and Myla's boxes is the same as 2 ft.

Step-by-step explanation:

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Given: Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft³ .

width=\dfrac{12}{2\times3}=2\ ft.

Myla has a storage box that is 4 ft. High, 2 ft. Long, and has a volume of 16 ft³.

width=\dfrac{16}{4\times2}=2\ ft.

Hence, the widths of Kyle and Myla's boxes is the same as 2 ft.

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3 years ago
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Answer:

See below.

Step-by-step explanation:

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