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mel-nik [20]
3 years ago
10

He tables represent two linear functions in a system.

Mathematics
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

8-22 is the answer ok thanks

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Write {4, 16, 36, 64, 100, 144} in set builder notation
docker41 [41]

Answer:

Here we are given with the numbers 4 16 36 64 100

So in these kind of questions we have to find what common pattern is prevailing so in this one:

Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:

16–4=12

36–16=20

64–36=28

100–64=36

So we have a new series 12 20 28 36 in this Subtracting every no from it's succeeding no gives a difference of 8 now in the latter series continues with the same pattern of difference of 8 and the series proceeds with next numbers 44 52 60 now these no gets added in the first original series as described as follows :

100+44=144

144+52=196

196+60=256

So the next 3 numbers are 144,196,256

5 0
3 years ago
CAN YOU PLEASEEE HELP ME IM DESPERATE AND NEED THE ANSWER ASAP
Juliette [100K]

Answer:

6(x-3)(X^2+4)(x+1)=0

real answers:

(x-3)=0

x=3

x+1=0

x=-1

This numbers are not real:

x^2+4=0

x^2=-4

\sqrt{x}= ±\sqrt{2}

6 0
4 years ago
How to find variables of these #2 & #3
Lubov Fominskaja [6]
So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles  like  \bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}

now.. for 3) will be the second picture below


\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}

8 0
3 years ago
Identify an equation in point-slope form for the line perpendicular to
Alik [6]

Answer:

C

Step-by-step explanation:

Perpendicular lines have the exact opposite slope of the other equation.

So the slope will be x or 1x. Plug in

-8 = 1(4) + b (b represents y-intercept) like y=mx+b

-8 = 4 + b (subtract 4 on both sides)

-12 = b

The equation is y = x - 12

C

solve

y + 8 = x - 4 (subtract 8 on both sides)

y = x - 12

7 0
4 years ago
Someone help and please make sure the answer is right
ELEN [110]

Answer:

Its right

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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