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kotegsom [21]
3 years ago
14

Rashad earned $662 by working five days a week at his full time job what average pay per day did he earn from full time work

Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0

Answer: $132.40

Step-by-step explanation:

To find the average, take the total amount of money, then divide it by the number of days he worked. So he worked 5 days a week, and got a total of $662, so divide. 662/5 to get $132.40.

Hope that helps :)

best of luck <3

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A 40 oz jar of peanut butter costs 5.25. how much does a 100 oz jar cost
Karolina [17]

Answer:

13.13

Step-by-step explanation:

5.25 x 100/40 is 13.125 which rounds up to 13.13

7 0
3 years ago
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OK SO HERES THE PROBLEM. MY BRAIN HURTS. PLZZZ help me with this math problem
jeka57 [31]

Oh Foxy, Foxy, how totally debilitated you must be !  Try to relax.  Nobody
enjoys a painful brain, and believe me, this problem is not worth it.

Let me put it to you this way:  What if the problem said . . .

-- Demarcus has $8 more than his sister.
-- His sister has $4.
-- How much money ' M ' does Demarcus have ?

If your brain didn't hurt, you could quickly solve this right in there.
You would know that Demarcus' money ' M ' = 8 + 4 .

That's <em>almost </em>exactly what the problem <em>does</em> say. 
Except it doesn't say he has "$8 more than his sister",
it says he has "at least" that much.
So you know that ' M ' is not exactly = 8 + 4, but that's the <u>least</u> it could be.
The actual amount of ' M ' is <u>more</u> than that.

Surely you can handle it from here, even with half of your brain
tied behind your back.

Take a good hard look at ' A ', and then go lie down.


7 0
3 years ago
2. A solar lease customer built up an excess of 6,500 kilowatt hours (kwh) during the summer using his solar
tia_tia [17]

9514 1404 393

Answer:

  a)  E = 6500 -50d

  b)  5000 kWh

  c)  the excess will last only 130 days, not enough for 5 months

Step-by-step explanation:

<u>Given</u>:

  starting excess (E): 6500 kWh

  usage: 50 kWh/day (d)

<u>Find</u>:

  a) E(d)

  b) E(30)

  c) E(150)

<u>Solution</u>:

a) The exces is linearly decreasing with the number of days, so we have ...

  E(d) = 6500 -50d

__

b) After 30 days, the excess remaining is ...

  E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days

__

c) After 150 days, the excess remaining would be ...

  E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system

The supply is not enough to last for 5 months.

3 0
2 years ago
The answer to this difficult question in my math book that I have to solve. Can you help me?
s2008m [1.1K]
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Hope this helps!
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Ray Of Light [21]

Answer:

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Step-by-step explanation:

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