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abruzzese [7]
2 years ago
13

Put decimals in order from smallest to largest and then find the median?

Mathematics
1 answer:
Alika [10]2 years ago
6 0

Answer:

0.11,0.4,0.42,0.5,0.8. The median would be 0.446

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The expression 3(x-9) is equivalent to<br> 3(x)+9.<br> 3(x)+3(9).<br> 3(x) – 9.<br> 3(x) – 3(9).
sukhopar [10]

Answer:

3(x) – 3(9)

Step-by-step explanation:

3(x-9)

Distribute the 3 to each term in the parentheses

3*x -3*9

3x -27

3 0
2 years ago
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I need help PLEASE!!!
Stella [2.4K]

9514 1404 393

Answer:

  y = -4/3x +23/2

Step-by-step explanation:

The tangent of interest is perpendicular to the radius at the given point on the circle. To find the perpendicular, it helps to know the slope of the radius segment. To find that, we need the center of the circle.

The center of the circle can be found by completing the square for each variable.

  (x^2 -2x) +(y^2 +4y) = 20

  (x^2 -2x +1) +(y^2 +4y +4) = 20 +1 +4

  (x -1)^2 +(y +2)^2 = 25

Comparing this equation to the standard form equation for a circle, we can find the center.

  (x -h)^2 +(y -k)^2 = r^2 . . . . . . . circle of radius r centered at (h, k)

The center of circle P is (1, -2).

__

The slope m' of the line segment between (1, -2) and (5, 1) is given by ...

  m' = (y2 -y1)/(x2 -x1)

  m' = (1 -(-2))/(5 -1) = 3/4

The slope m of the perpendicular line is the opposite reciprocal of this, so is ...

  m = -1/m' = -1/(3/4) = -4/3

The y-intercept of the desired line can be found from ...

  b = y -mx . . . . . . . for m=-4/3 and (x, y) = (5, 1)

  b = 1 -(-4/3)(5) = 23/3

Then the equation of tangent line AB is ...

  y = mx +b

  y = -4/3x +23/3

6 0
2 years ago
4 (3x + 2)-6<br> I neeeed help
yuradex [85]

Answer:

12x - 2

Step-by-step explanation:

Step 1: Write expression

4(3x + 2) - 6

Step 2: Distribute 4

12x + 8 - 6

Step 3: Combine like terms

12x - 2

5 0
3 years ago
Please help me now!<br><br> I will give brainly
olga2289 [7]
1) 15
2)6
3)9
Hope this helps!
7 0
2 years ago
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Please help. the question is in the picture.
Harlamova29_29 [7]

We have measures of all tree sides of the both triangles,

so we can use SSS to check if the triangles are similar.

|ED|/|AB| =5/10=1/2

|DC|/|BC| = 4/8 = 1/2

|EC|/|AC| = 6/12 = 1/2

We see that all tree pairs are in proportion, so these triangles ΔABC and ΔEDC are similar.

We have enough information to prove that ΔABC similar to ΔEDC.

8 0
3 years ago
Read 2 more answers
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