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Alexxandr [17]
3 years ago
5

I am ust typing this so it will let me post this But Please Help

Mathematics
1 answer:
andre [41]3 years ago
4 0

Answer:

{4}^{3}  = 64

Step-by-step explanation:

\frac{ {4}^{8} }{ {4}^{5} }  =  {4}^{3}

Subtract the numerator exponent from the denominator exponent.

8 - 5

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3 0
3 years ago
Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.) a = 3.0, b = 4.0, C = 58°
KATRIN_1 [288]

Answer

A = 46.3°

B = 75.7°

c = 3.5

Explanation

We will be using both Cosine and Sine rule to solve this.

For Cosine rule,

If a triangle ABC has angles A, B and C at the points of the named vertices of the tringles with the sides facing each of these angles tagged a, b and c respectively, the Cosine rule is given as

c² = a² + b² - 2ab Cos C

a = 3.0

b = 4.0

C = 58°

c² = 3² + 4² - 2(3)(4)(Cos 58°)

c² = 9 + 16 - (24)(0.5299)

c² = 25 - 12.72 = 12.28

c = √12.28 = 3.50

To find the other angles, we will now use Sine Rule

If a triangle ABC has angles A, B and C at the points of the named vertices of the tringles with the sides facing each of these angles tagged a, b and c respectively, the sine rule is given as

\frac{\text{ Sin A}}{a}=\frac{\text{ Sin B}}{b}=\frac{\text{ Sin C}}{c}

So, we can use the latter parts to solve this

\frac{\text{ Sin B}}{b}=\frac{\text{ Sin C}}{c}

B = ?

b = 4.0

C = 58°

c = 3.5

\begin{gathered} \frac{\text{ Sin B}}{4}=\frac{\text{ Sin 58}\degree}{3.5} \\ \text{ Sin B = }\frac{4\times\text{ Sin 58}\degree}{3.5}=0.9692 \\ B=Sin^{-1}(0.9692)=75.7\degree \end{gathered}

We can then solve for Angle A

The sum of angles in a triangle is 180°

A + B + C = 180°

A + 75.7° + 58° = 180°

A = 180° - 133.7° = 46.3°

Hope this Helps!!!

7 0
1 year ago
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