Let’s make two equations. D being dimes and Q being quarters.
D+Q=100
0.1d+0.25q=14.05
Now, let’s multiply the first equation by -0.10 so that we can cancel out D.
-0.1D-0.1Q=-10
0.1d+0.25q=14.05
Let’s solve
0.15Q=4.05
Let’s divide.
Q=27
So there’s 27 Quarters. Since there are 100 in total, there must be 73 dimes.
Let’s make sure this adds up.
0.25(27)+0.1(73)
6.75+7.30
14.05
So there’s 27 Quarters.
Answer:
-40
Step-by-step explanation:
Try rearranging and factoring -8y-2c-2b-8x-2a:
This is equal to -8(x + y) -2(a + b + c).
Since x + y = 7, we have:
-8(7) -2(a + b + c)
and since a + b + c = 8, we end up with:
-56 - 2(8), or
-56 - 16 = -40
Answer:
Step-by-step explanation:
<h3><u>Given data:</u></h3>
Theta = θ = 35°
Radius = r = 10 ft.
<h3><u>Required:</u></h3>
Arc length = ?
<h3><u>Formula:</u></h3>
<h3><u>Solution:</u></h3>
Put the givens in the above formula
![\displaystyle Arc \ length = 2 (3.14)(10)(\frac{35}{360} )\\\\Arc \ length = 2(3.14)(10)(0.097)\\\\Arc \ length = 6.11 \ ft.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Arc%20%5C%20length%20%3D%202%20%283.14%29%2810%29%28%5Cfrac%7B35%7D%7B360%7D%20%29%5C%5C%5C%5CArc%20%5C%20length%20%3D%202%283.14%29%2810%29%280.097%29%5C%5C%5C%5CArc%20%5C%20length%20%3D%206.11%20%5C%20ft.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
