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Zigmanuir [339]
3 years ago
13

I need help with 16, 17, 18, 19, 20 & 21 please.

Mathematics
1 answer:
Snezhnost [94]3 years ago
3 0

Answer:

Step-by-step explanation:

Number 16. You should put yes

Number 17 put no

number 18 is yes

Number 19 is yes

number 20 is no

number 20 is no

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10. Circle the irrational number in the list below.<br> √196<br> 7.27<br> in/a<br> √15
VashaNatasha [74]

Answer:

Step-by-step explanation:

7.27 is irrational because it has repeating digits(27 is infinite, 7.272727...)

7 0
2 years ago
What’s the value of 3x+5 when x=2
Zepler [3.9K]

Answer:

11

Step-by-step explanation:

First you replace x with 2

3(2)+5

You open the bracket

6+5

Then you add

11

6 0
4 years ago
Read 2 more answers
As a ship approaches the dock, it forms a 70 angle between the dock and the lighthouse. At the lighthouse, an 80 angle is formed
Trava [24]

Answer:

The distance from the ship to the dock is approximately 5.24 miles

Step-by-step explanation:

From the parameters given in the question, we have;

The angle formed between the dock and the lighthouse = 70°

The angle formed between the dock and the lighthouse at the ship = 80°

The distance between dock and the lighthouse = 5 miles (From a similar question online)

By sine rule, we have;

\dfrac{a}{sin(A)} = \dfrac{b}{sin(B)} = \dfrac{c}{sin(C)}

Therefore, we have;

\dfrac{5}{sin(70^{\circ})} = \dfrac{The \ distance \ from \ the \ ship \ to \ the \ dock}{sin(80^{\circ})}

\therefore The \ distance \ from \ the \ ship \ to \ the \ dock = sin(80^{\circ}) \times \dfrac{5}{sin(70^{\circ})}

sin(80^{\circ}) \times \dfrac{5}{sin(70^{\circ})} \approx 5.24 \ mi

Therefore;

The distance from the ship to the dock ≈ 5.24 miles

7 0
3 years ago
Mr. Jones wants to add a cement path around his new pool. The pool has a radius of 7 feet. The cement path will be 1 foot wide a
Aleonysh [2.5K]

The square footage of the path is 47.1 ft²

The area of a circle is:

A = πr²

Where r is the radius of the circle.

Let us assume that the pool is a circle.

Given that the pool has a radius (r₁) of 7 feet and a path 1 foot wide would go round the pool.

Radius of pool and cement path (r₂) = 7 ft + 1 ft = 8 ft.

The square footage of the path =  πr₂² - πr₁² = π*8² - π * 7² = 47.1 ft²

Hence The square footage of the path is 47.1 ft²

Find out more at: brainly.com/question/23328170

7 0
2 years ago
Please help answer ASAP
mote1985 [20]
The answer is false it is the opposite from 100 percent
3 0
3 years ago
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