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Zepler [3.9K]
2 years ago
7

Mr. Jones wants to add a cement path around his new pool. The pool has a radius of 7 feet. The cement path will be 1 foot wide a

nd
go all the way around the pool. What is the square footage of the path?
Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
7 0

The square footage of the path is 47.1 ft²

The area of a circle is:

A = πr²

Where r is the radius of the circle.

Let us assume that the pool is a circle.

Given that the pool has a radius (r₁) of 7 feet and a path 1 foot wide would go round the pool.

Radius of pool and cement path (r₂) = 7 ft + 1 ft = 8 ft.

The square footage of the path =  πr₂² - πr₁² = π*8² - π * 7² = 47.1 ft²

Hence The square footage of the path is 47.1 ft²

Find out more at: brainly.com/question/23328170

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Nadia says the hypotenuse of the right triangle has a length of 73 because the Pythagorean theorem states that (28+45)squared eq
Setler79 [48]

Answer: Her solution is incorrect. The hypotenuse is 53 units

Step-by-step explanation: The error occurred when she quoted the Pythagorean theorem. She added up both sides and squared them and made the answer equal to the square of the hypotenuse. She was supposed to have squared them first, before adding up.

The Pythagorean (or Pythagoras) theorem states that the sum of the squares of two sides of a right angled triangle equals the square of the hypotenuse of the triangle. That is, in triangle ABC, if the hypotenuse is given as line AC, the Pythagoras theorem states that

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Where AC is the hypotenuse and AB and BC are the other two sides.

In Nadia’s solution, if the hypotenuse is given as 73, and the other two sides are 28 and 45, then the Pythagorean theorem properly expressed would be as follows;

73^2 = 28^2 + 45^2

5329 = 784 + 2025

5329 ≠ 2809

As we have determined, writing out the expression as

73^2 = (28 + 45)^2 is very incorrect as this is not the Pythagorean theorem and of course, the triangle cannot have 73 as its hypotenuse as we have determined by properly writing out the Pythagorean theorem.

The correct solution is as follows;

AC^2 = AB^2 + BC^2

AC^2 = 28^2 + 45^2

AC^2 = 784 + 2025

AC^2 = 2809

Add the square root sign to both sides of the equation

AC = 53

Therefore, the hypotenuse is 53 units

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