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Mashutka [201]
3 years ago
11

Help me yall :)))) please

Mathematics
2 answers:
xenn [34]3 years ago
3 0

Answer:

C

Step-by-step explanation:

I looked it up

makvit [3.9K]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Please give give brainlist

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Please help I'm so confused.
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Factorize x^4 + 2x^3 - 11x^2 - 12x + 36 <br><br>I need the steps.<br>Please i need this for today.
Yuliya22 [10]

x^4 +2x^3 -11x^2-12x+36\\ \\=x^4-2x^3+4x^3-8x^2-3x^2 +6x-18x+36\\\\=x^3(x-2)  +4x^2(x-2)  -3x(x-2)   -18(x-2)\\\\=(x-2)(x^3 +4x^2 -3x -18)\\\\=(x-2)(x^3+3x^2+x^2+3x-6x-18)\\\\=(x-2)\textbf{[}x^2(x+3)+x(x+3)-6(x+3)\textbf{]}\\\\=(x-2)(x+3)(x^2 +x -6)\\\\=(x-2)(x+3)(x^2 +3x -2x-6)\\\\=(x-2)(x+3)\textbf{[}x(x+3) -2(x+3)\textbf{]}\\\\=(x-2)(x-2)(x+3)(x+3)\\\\=(x-2)^2(x+3)^2

6 0
2 years ago
Question 51 ptsThe point (-4,-2) lies on a circle. What is the length of the radius of this circle if thecenter is located at (-
forsale [732]

Given,

The coordinates of the point on the circle is (-4, -2).

The coordinates of the center of the circle is (-8, -10).

Reuired

The length of the center of the circle.

By using the distance formula, the radius of the circle can be calculated.

The distance formula is,

Distance=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Substituting the value of the coordinates of the points,

\begin{gathered} Distance=\sqrt{(-10-(-2))^2+(-8-(-4))^2} \\ =\sqrt{(-10+2)^2+(-8+4)^2} \\ =\sqrt{(-8)^2+(-4)^2} \\ =\sqrt{64+16} \\ =\sqrt{80} \\ =\sqrt{4\times4\times5} \\ =4\sqrt[]{5} \end{gathered}

Hence,

3 0
1 year ago
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