<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
I believe it’s the second one
Answer:
1. (q² + 8) - (4q² + 1)
Simplify each term.
q²+8−4q²−1
Simplify by adding terms.
−3q²+7
2. (3x + 7x² - 6) - (5x² + x + 9)
Simplify each term.
3x+7x²−6−5x²−x−9
Simplify by adding terms.
Tap for more steps...
2x²+2x−15
Step-by-step explanation:
Multiply the probability by the cost of the accident:
14,886.05 x 0.071 = 1056.91
Now add the overhead cost:
1056.91 + 110 = 1166.91
The closest answer to this is number D.
Answer:
I uhh need the question.. lol
Step-by-step explanation:
cat is 31%
dog is 42%
hamster is 19%
fish is 8%
62+84+38+16=200
62/200=0.31
84/200=0.42
38/200=0.19
16/200=0.08
Have a nice day!
