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liubo4ka [24]
3 years ago
8

How many solutions does the nonlinear system of equations graphed below have?

Mathematics
1 answer:
wel3 years ago
3 0

Answer:

they have three solutions  

HOPE IT HELPS

TAHE CARE

Step-by-step explanation:

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Help me, correct answers appreciated ​
-BARSIC- [3]

Answer:

No

Step-by-step explanation:

-6 is X

-10 is Y

-10 is smaller than - 8

5 0
3 years ago
Read 2 more answers
While on vacation, Kayla goes for walks 3 times a day. Her morning walk is 1 1/2 times the distance of her afternoon walk. Her e
natta225 [31]

Answer: 2 miles

Step-by-step explanation:

Afternoon-x; morning- 1.5x; Evening: 1/2x

Make a equation: 1.5x+x+1/2=6

2.5x+1/2x=6

5/2x+1/2x=6

6x=12

x=2

6 0
3 years ago
WHOEVER IS RIGHT GETS BRAINLIST
pochemuha
The answer to the first question is b
I don’t know the answer to the second one sorry
4 0
3 years ago
Jeanette wants to raise $3,200 in a marathon fundraiser. Her sponsers will donate
raketka [301]

Answer:

92

Step-by-step explanation:

= 3200 ÷ 35

= 91.43

round up to nearest whole number

= 92 km

5 0
3 years ago
A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam. Find
Nonamiya [84]

The tension in both cables are calculated as; T₁ = 127.63 N and T₂ = 185.48 N

<h3>How to find the Tension in Suspended Cables?</h3>

Resolving forces in the y direction gives us;

T₁ sin 29° + T₂ sin 53° = 210  ------(eq 1)

Resolving forces in the horizontal direction gives;

T₁ cos 29° = T₂ cos 53°   ----(eq 2)

T₁ = T₂ cos 53°/cos 29°

Thus;

(T₂ cos 53°/cos 29°)sin 29° + T₂ sin 53° = 210  

0.3336T₂ + 0.7986T₂ = 210

T₂ = 210/1.1322

T₂ = 185.48 N

Thus;

T₁ = 185.48 cos 53°/cos 29°

T₁ = 127.63 N

Read more about Tension in Cables at; brainly.com/question/11653585

#SPJ1

7 0
2 years ago
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