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Papessa [141]
3 years ago
7

If (x)= X-2 and d(x) = x + 3, what is the domain of (cd)(x)?

Mathematics
1 answer:
Nata [24]3 years ago
3 0

Answer:

Option (2)

Step-by-step explanation:

Given functions are,

c(x) = \frac{5}{x-2}

d(x) = x + 3

Equation of the composite function will be,

(cd)(x) = c(x) × d(x)

          = \frac{5}{(x-2)}\times (x+3)

          = \frac{5(x+3)}{(x-2)}

This function is defined only when denominator is not equal to zero.

(x - 2) ≠ 2

Therefore, for real numbers except x = 2 will be the domain of the composite function.

Option (2) will be the answer.

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The force, F (Newtons), between two objects is inversely proportional to the square of the distance, d (metres), between them.
snow_lady [41]

Answer:

d = 1.46 m

Step-by-step explanation:

We'll begin by obtaining the relationship between the force (F) and the distance (d). This can be obtained as follow:

From the question given above,

F is inversely proportional to square of d. This can be written as:

F ∝ 1/d²

F = K/d²

Cross multiply

K = Fd²

But:

Force (F) = 0.006 N

Distance (d) = 4 m

Constant (K) =?

K = Fd²

K = 0.006 × 4²

K = 0.006 × 16

K = 0.096 Nm²

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F = K/d²

F = 0.096 / d²

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Force (F) = 0.045 N

Constant (K) = 0.096 Nm²

Distance (d) =?

F = K/d²

0.045 = 0.096 / d²

Cross multiply

0.045 × d² = 0.096

Divide both side by 0.045

d² = 0.096 / 0.045

Take the square root of both side.

d = √(0.096 / 0.045)

d = 1.46 m.

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Ur answer .. Check it out ..

Plz mark me as brainliest ..

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