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Ket [755]
2 years ago
14

Solve for x (x+3)^2 thanks

Mathematics
2 answers:
IrinaK [193]2 years ago
7 0
Answer : X^2+6x+9
(X+3)(x+3)
Deffense [45]2 years ago
3 0

Answer:

X = -3

Step-by-step explanation:

(X + 3) ( X + 3)

(x^2+3x)+(3x+9)

X(X+3) + 3(X+3)

(X+3)(X+3)

X+3= 0

X = -3

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Find the h.c.f by prime factorization method 27, 30​
Orlov [11]

Answer:

Find it yourself . you must try yourself. rate me plzs

7 0
2 years ago
If x is equal to -6 which equality is true​
Papessa [141]

Answer:

-5 - 3x > 10

Step-by-step explanation:

x = -6

Plug in the x value for each inequality:

-5 - 3(-6) > 10

-5 + 18 > 10

13 > 10

True

-3 - 5(-6) < -14

-3 + 30 < -14

27 < -14

False

1 - 2(-6) > 13

1 + 12 > 13

13 > 13

False

2 - (-6) < -3

2 + 6 < -3

8 < -3

False

Only one of these is true; that is the answer.

8 0
2 years ago
Leah claims that these figures are not similar. When she compared the heights, she wrote 27. Then she compared the bases and got
Flauer [41]

Answer:

<h2>Leah is actually wrong, because those rectangles are similar.</h2>

Step-by-step explanation:

Remember that similarity is about having proportional sides and congruent angles. When we have congruent sides, then those rectangles are congruent not similar.

In this case, to find the similarity, Leah should compare bases and heights thorugh division, because the ratio between heights and the ratio between bases must be equal. So, let's divide.

\frac{21}{6}=3.5

\frac{7}{2}=3.5

As you can observe, both ratios are equal.

Therefore, those rectangles are congruent.

4 0
3 years ago
Ac is tangent to circle o at point c what is the length of ac?
MissTica

Answer:

The Answer is 12

Step-by-step explanation:

Use Pythagorean theorem. AB=8 and BO=5 We still need to find AO

AO=AB+BO

8+5

AO=13

Now solve for AC

AC^2 + OC^2= AO^2

AC^2+5^2=13^2

AC^2+ 25=169

AC^2=144

AC= 12

5 0
3 years ago
Write the set builder notation {8}
timofeeve [1]

Step-by-step explanation:

\{8 \} =  \{x : x = n, \: n \in \:N, \:   \: 7 < n > 9 \: \}

5 0
3 years ago
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