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dybincka [34]
3 years ago
13

Ken paid $12 for two magazines. the cost of each magazines with a multiple of 3. what is the possible prices of the magazines

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
5 0
6$ per magazines because it's a multiple of 3
alexira [117]3 years ago
5 0
$6 per magazine :)))
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Write an expression to describe the sequence below. Use n to represent the position of a term in the sequence, where n = 1 for t
likoan [24]

Hello from MrBillDoesMath!

Answer:

a(n) = -3n  , n>= 1

Discussion:

a(1) = -3

a(2) = -6

a(3) = -9

a(4) = -12

The pattern looks like a(n) = -3n

Thank you,

MrB

6 0
3 years ago
Help. I need help with these questions ( see image).<br> Please show workings.
Andrew [12]

9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

  \text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0
3 years ago
The edge of each cube used to build this rectangular prism is 12 inch long. Which equation shows the volume of the prism, in cub
Sveta_85 [38]

Answer:

(4/2 × 2/2 × 3/2) in.³ =3 in.³

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
This shape is made using three semicircles The smaller semicircle have diameters of 10cm Calculate the shaded area Take 3.142 an
CaHeK987 [17]

Answer:

The shaded area is 314.2 cm²

Step-by-step explanation:

Here we have the diameter, d₁ of the smaller semicircles as 10 cm

We note that the larger semicircle is subtended (bounded) by the two smaller semicircles;

1 shaded small semicircle and the other is blank

Therefore, the diameter, d₂ of the large semicircle = 10 + 10 = 20 cm

Also the area of the shaded figure consists of the removal of one small semicircle and the addition of the other semicircle to the area of the larger semicircle such that the area of the shaded figure is as follows

Shaded area of figure = π·d₂²/4 + π·d₁²/4 - π·d₁²/4 = π·d₂²/4 = π×20²/4 = 100×3.142 = 314.2 cm²

Shaded area = 314.2 cm².

6 0
3 years ago
PLEASE HELP ASAP WILL GIVE BRAINLIEST!
Alex777 [14]

Answer:

1.01

Step-by-step explanation:

Mean with outliner = (39.55 + 40.51 + 41.01 + 37.76+ 35.32 + 33.28 + 34.38 + 36.48 + 39.87 + 50.32 + 40.59 + 41.71)/12 = 39.23 seconds.

In this case, the outlier comes to be the data: 50.32. If we don't consider that data point, the mean equals:

Mean wihout outliner = (39.55 + 40.51 + 41.01 + 37.76+ 35.32 + 33.28 + 34.38 + 36.48 + 39.87 + 40.59 + 41.71)/11 = 38.22

The difference is:  39.23 - 38.22 = 1.01

7 0
3 years ago
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