See the attached picture:
6% = 1200
9% = 2400
12% = 3800
The answer is 75% because 150/200 converted to a percent is 75%
150/200= 0.75
0.75 x 100 = 75%
Since 7 is greater than 5, you input it into the last equation.
2•(7) -7
14-7
7
The answer is 7!
Answer:
A sample size of 79 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.09?
A sample size of n is needed.
n is found when M = 0.09. So






Rounding up to the nearest whole number.
A sample size of 79 is needed.