Question

Can somebody help me

Answer 1

Plot the intercepts:

y=-1

x=?

to find the x intercept, you dont solve the equation as it is solved in the slope-intercept form. instead, you simply plug in 0 for y:

0=1/4x-4

0=1/4x-4+4

4=1/4x

4/1/4=1/4x

1/4=0.25

x=16

revise:

y=(0, -1)

x=(16,0)

graph the slope for y=-1/2x-1: start from say point (0,-1)

graph the slope for y=1/4x-4: start from say point (16,0) ; you can just ise the intercept (0,-4) since the graph is diluted small...anyways

the points intersect at (4, -3) so thats the solution to the equations

NOTE: when graphing slopes that are negative either the numerator or the denominator can be graphed negative. so I graphed the first equation with the numerator as the positive and the denominator as the negative : rise= 1 ; run: -2. once i got to the end of the provided graph i started from the -1 y-intercept again and graphed the equation using: rise=-1; run=2

*graphing messes me up, too*