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Afina-wow [57]
3 years ago
10

2×3×10 to the 9th power = (1×10 to the 3rd power) (2×3 × 10n)​

Mathematics
1 answer:
stiks02 [169]3 years ago
3 0

Answer:

this is what my calculator said sorry: 1.0077696E16

Step-by-step explanation:

calculator

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Kindly solve this question 6 too !!
Shkiper50 [21]

Answer:

x=1

Step-by-step explanation:

~~~~~x = \dfrac{1}{2 - \dfrac 1{2-\dfrac{1}{2-x}}}\\\\\\\implies x = \dfrac{1}{2 - \dfrac 1{\dfrac{4-2x-1}{2-x}}}\\\\\\\implies x= \dfrac{1}{2 - \dfrac{2-x}{3-2x}}\\\\\\\implies x = \dfrac{1}{\dfrac{6-4x-2+x}{3-2x}}\\\\\\\implies x = \dfrac{3-2x}{4-3x}\\\\\\\implies 4x -3x^2 = 3-2x\\\\\\\implies 3x^2 -4x +3-2x = 0\\\\\\\implies 3x^2 -6x +3 = 0\\\\\\\implies 3(x^2 -2x +1) =0\\\\\\\implies x^2 -2x +1 = 0\\\\\\\implies (x-1)^2 = 0\\\\\\\implies x -1 = 0\\\\\\\implies x = 1

7 0
2 years ago
2. You throw a softball straight up into the air at a velocity of 30 feet per second. You release the softball at a height of 5.
nadya68 [22]

Answer:

-16t^2+30t+5.8

Step-by-step explanation:

We are given that

Initial velocity=30 ft/s

Initial position=s_0=5.8 ft

We have to write a mathematical model for height of the softball by using the position equation

The position equation on Earth's surface is given by

h(t)=-16t^2+v_0t+s_0

Where v_0= Initial velocity

s_0=Initial position

Substitute the values in the equation then, we get

h(t)=-16t^2+30t+5.8

Hence, the mathematical model for height of the softball is given by

-16t^2+30t+5.8

5 0
4 years ago
which method for comparing fractions were you unaware of before reading? use it to compare 2/3 and 3/4​
wolverine [178]

Good morning

______

Answer:

2/3 < 3/4​

___________________

Step-by-step explanation:

2/3 = (2*4)/(3*4)=8/12

3/4 = (3*3)/(4*3)=9/12

Since 9/12>8/12 then 3/4>2/3

:)

6 0
3 years ago
What is 15 divided by 10.05 in the standard algorithm 1 way​
andriy [413]

Answer:4566878888

Step-by-step explanation:

6 0
3 years ago
What is the constant of vanation,<br>of the line y = for through (3.18) and (5,30)?​
Naily [24]

the constant of variation or namely its slope will be

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{18})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{30}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{30-18}{5-3}\implies \cfrac{12}{2}\implies 6

8 0
3 years ago
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