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2 years ago

9

How far will i travel if i am driving @75kmh for 18 mins. can the distance over speed applies?

1 answer:

Roman55 [17]2 years ago

8 0

Answer:

22.5 km

Step-by-step explanation:

Speed = distance/time

Given speed = 75km/h

time = 18 mins

Distance = ?

Given the speed is in km/h , convert the time from minutes to hour .

18/60 = 0.3 hours

Therefore,

75 = distance/0.3

Cross multiply

75 x 0.3 = distance

22.5 = distance

Distance = 22.5 km

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A baseball player makes $12 million per year. Express his salary in dollars per minute.

Irina-Kira [14]

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Then do $12million divided by your final answer from before to finish!

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3 years ago

Find the value of X in each of the following X/3-2=6 <br>X/5+1 =5<br><br>please help me

natita [175]

Answer:

a) x = 24

b) x = 20

Step-by-step explanation:

a) x÷3 - 2 = 6

+2 +2

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2 years ago

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2 years ago

Tom is playing football . He carries the ball 7 1/3 yards and then goes backwards 2 feet how far did Tom Cary the ball in feet a

Katen [24]

Answer:

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2 years ago

Prove ΔPAB is isosceles.

Licemer1 [7]

Answer:

See explanation

Step-by-step explanation:

If $PX\cong PY,$ then triangle PXY is isosceles triangle. Angles adjacent to the base XY of an isosceles triangle PXY are congruent, so

$\angle 1\cong \angle 2$

and

$m\angle 1=m\angle 2$

Angles 1 and 3 are supplementary, so

$m\angle 3=180^{\circ}-m\angle 1$

Angles 2 and 4 are supplementary, so

$m\angle 4=180^{\circ}-m\angle 2$

By substitution property,

$m\angle 4=180^{\circ}-m\angle 2=180^{\circ}-m\angle 1=m\angle 3$

Hence,

$\angle 3\cong \angle 4$

Consider triangles APX and BPY. In these triangles:

$PX\cong PY$ - given;
$\angle 5\cong \angle 6$ - given;
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so $\triangle APX\cong \triangle BPY$ by ASA postulate.

Congruent triangles have congruent corresponding sides, then

$AP\cong BP$

Therefore, triangle APB is isosceles triangle (by definition).

6 0

3 years ago