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Nuetrik [128]
3 years ago
14

Please, please HELP!!!

Mathematics
2 answers:
kupik [55]3 years ago
5 0

Answer:

circumference = 37.68 (37.7 if you're rounding it)

Area = 113.04 (113.1 if you're rounding it)

Step-by-step explanation:

The formula for circumference is C=2πr (2 times pi times radius)

If the diameter is 12, the radius is 6.

2 x 3.14 x 6 = 37.7

The formula for area is A=πr2 (pi x radius to the second power)

The radius is 6. Six to the second power is 36.

36 x 3.14 = 113.04

Rashid [163]3 years ago
4 0

Answer:

circumference: 37.7

area: 113.1

Step-by-step explanation:

for the future look up '___ of a circle'

and enter the radius (if u are given the diameter divide it by 2)

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weqwewe [10]

Answer:

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

Step-by-step explanation:

1) Data given and notation  

n=180 represent the random sample taken  

X=125 represent the number of americans between 17 to 24 that not qualify for the military

\hat p=\frac{125}{180}=0.694 estimated proportion of americans between 17 to 24 that not qualify for the military

p_o=0.75 is the value that we want to test  

\alpha=0.05 represent the significance level  

Confidence=95% or 0.95  

z would represent the statistic (variable of interest)  

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that less than 75% of Americans between the ages of 17 to 24 do not qualify for the military :  

Null hypothesis: p\geq 0.75  

Alternative hypothesis:p < 0.75  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.  

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

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Answer:

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What is x in this geometry equation?​
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Ok, so IDK if I'm about to do this problem right, but here we go;


so first, lets change these all to decimals (I more of a decimal gal)

3 1/2 = 3.5
3 2/3 = 3.6666 (repeating)
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So now, just order them from greatest to least.  

3.66666, 3.6, 3.5, 3.375.  

Now, change them back to fractions.  
3 2/3, 3 3/5, 3 1/2, 3 3/8


So, if I'm correct, the answer is 3 2/3%, 3 3/5%, 3 1/2%, 3 3/8%
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B. 46 feet because 132/12=11 and 12+12+11+11=46

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