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Elena-2011 [213]
4 years ago
7

X-y = -10 2x+4y=22 substitution

Mathematics
1 answer:
Tema [17]4 years ago
4 0

Answer:

[1]    x - 4y = 22

  [2]    2x + 5y = -21

Step-by-step explanation:

Solve equation [1] for the variable  x  

 

 [1]    x = 4y + 22

// Plug this in for variable  x  in equation [2]

  [2]    2•(4y+22) + 5y = -21

  [2]    13y = -65

// Solve equation [2] for the variable  y  

  [2]    13y = - 65  

  [2]    y = - 5  

// By now we know this much :

   x = 4y+22

   y = -5

// Use the  y  value to solve for  x  

   x = 4(-5)+22 = 2

I am sorry if I get it wrong.

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Find the area of the shaded region 6cm 6cm
Mashutka [201]
Hope this helps! the answer is option (A). if you still don’t understand after looking at my solution feel free to clarify ya

4 0
3 years ago
Paul opened a bakery. The net value of the bakery (in
Umnica [9.8K]

Answer:

1) 2(t - 7)(t + 1)

2) $32,000

Step-by-step explanation:

v(t) = 2t² - 12t - 14

v(t) = 2(t² - 6t - 7) = 2(t - 7)(t + 1)

x = -b/2a = 6/2 = 3

y = 2(3)² - 12(3) - 14 = -32

(3, -32) means at 3 months, -32 thousand dollars

7 0
3 years ago
Read 2 more answers
مجموع اعداد طبیعی از ۱ تا ۱۰۰ چند میشود؟​
Nuetrik [128]

Answer:

ooh sorry bro but i can't understand. pls.. write it in english.. what subject is this???

4 0
3 years ago
A godown is 40m long,30m wide and 9m high. How many cuboidal boxes can be stored in it, if the dimension of each box is 2mx1.2x4
sergiy2304 [10]

Answer: There are 10000 cuboidal boxes can be stored in the godown.

Step-by-step explanation:

Since we have given that

Dimensions of godown will be

40 m, 30 m, 9 m .

Dimensions of cuboidal boxes will be

2 m, 1.2 m, 45 cm

As we know Number of cuboidal boxes is given by

\frac{\text{ Volume of godown }}{\text{ Volume of cuboidal box}}\\\\=\frac{40\times 30\times 9}{2\times 1.2\times 0.45}\\\\=10000

Hence, there are 10000 cuboidal boxes can be stored in the godown.

4 0
3 years ago
Im learning about Recursive and Explicit in Pre-Calc, and it says to use the rule to write the first three terms of each sequenc
Tems11 [23]

Hello,

4. you have sequences defined by the first term and a recursive relation.

a_1=3\\\\a_n=2a_{n-1} \ \ \text{ for n}> 1

Take n = 2, it gives

a_2=2a_1 , right?

But you know a_1=3

so a_2=2a_1=2*3=6

This is the second term. You are asked to find the first three terms.

Now, let's take n = 3

a_3=2a_2=2*6=12

So the first three terms are 3, 6, 12.

6.

a_1=12\\\\a_2=\dfrac{1}{2}a_1+1=\dfrac{12}{2}+1=6+1=7 \\ \\a_3=\dfrac{1}{2}a_2+1=\dfrac{7}{2}+1=\dfrac{9}{2}

8.

a_1=10\\ \\a_2=-3a_1=-3*10=-30\\\\a_3=-3a_2=-3*(-30)=90

10.

a_1=2\\\\a_2=-1\\\\a_3=a_2+a_1=-1+2=1\\\\a_4=a_3+a_2=1-1=0

Do not hesitate if you have any question.

Thank you

8 0
4 years ago
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