2nd or 3rd option I hope I narrowed it down
Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Answer:
There will be 13 songs in the final album.
Step-by-step explanation:
i) number of songs expected = 16 songs
ii) the band wrrites 62.5% more
therefore the band writes 
songs
iii) During the editing process 50% of the songs are removed.
Therefore there will be in the final album = 
songs.
Answer: b: h=2a/b1+b2
Step-by-step explanation:
