The slope of (-2, -19) and (-12, 11)

27. The average hourly wage of workers at a fast food restaurant is $7.25/hr

morpeh [17]

Answer:

0.0668 = 6.68% probability that the worker earns more than $8.00

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The average hourly wage of workers at a fast food restaurant is $7.25/hr with a standard deviation of $0.50.

This means that $\mu = 7.25, \sigma = 0.5$

If a worker at this fast food restaurant is selected at random, what is the probability that the worker earns more than $8.00?

This is 1 subtracted by the pvalue of Z when X = 8. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8 - 7.25}{0.5}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% probability that the worker earns more than $8.00

8 0

3 years ago

What’s the answer in neeeeeeeeed it………

Aneli [31]

Answer:

10x

Step-by-step explanation:

3 0

2 years ago

Anybody yooo plzzzzzz

Elena-2011 [213]

Answer:

what do you have to do this?

Step-by-step explanation:

what grade and type of math is this?

6 0

3 years ago

Which number line shows the solutions to n > 3?ヽ(°◇° )ノ

balu736 [363]

It is the first number line :)

3 0

3 years ago

Read 2 more answers

The length of the human pregnancy is not fixed. It is known that it varies according to a distribution which is roughly normal,

fgiga [73]

Answer:

a) Figure attached

b) $P(234$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(234$

And we can find this probability with this difference:

$P(-2$

An we know using the graph in part a that this area correspond to 0.95 or 95%

c) $P(250$

And we can find this probability with this difference:

$P(-1$

An we know using the graph in part a that this area correspond to 0.95 or 34+34+13.5+2.35%=83.85%

d) $P(X$

And using the z score we got:

$P(X$

And that correspond to approximately 0.15%

Step-by-step explanation:

Part a

For this case we can see the figure attached.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part b

Let X the random variable that represent the length of human pregnancy of a population, and for this case we know that:

Where $\mu=266$ and $\sigma=16$

We are interested on this probability

$P(234$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(234$

And we can find this probability with this difference:

$P(-2$

An we know using the graph in part a that this area correspond to 0.95 or 95%

Part c

$P(250$

And we can find this probability with this difference:

$P(-1$

An we know using the graph in part a that this area correspond to 0.95 or 34+34+13.5+2.35%=83.85%

Part d

We want this probability:

$P(X$

And using the z score we got:

$P(X$

And that correspond to approximately 0.15%

5 0

3 years ago