Answer:
the y intercept should be 0
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
The price would go down as people would be more willing to buy cheaper potatoes and the producers would want to sell them for a lower price to get rid of them easy and fast.
Answer:
170
Step-by-step explanation:
Equations derived from given info.
Use some substitution now.
- P=2(E+40)
- J=E+40
- P+J+E=300
Substitute first and second equation into third.
- 2(E+40)+E+40+E=300
- 2E+80+E+40+E=300
- 4E+120=300
- 4E=180
- E=45
Emily has 45 stickers. But we want to know what Peter has.
Use P=2(E+40)
Peter has 170 stickers.
Step-by-step explanation:
Take the first derivative


Set the derivative equal to 0.




or

For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).
For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.
Since we are going to Positve to negative slope, we have a local max at x=-1
Plug in -1 for x into the original function

So the local max is 2 and occurs at x=-1,
For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.
Since we are going to decreasing to increasing, we have minimum at x=1,
Plug in 1 for x into original function


So the local min occurs at -2, at x=1