Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
The answer is 350.
<em>
m= minutes</em>
Plan 1: 9+0.13<em>m</em>
Plan 2: 23+0.09<em>m</em>
9+0.13<em>m</em> = 23+0.09<em>m</em>
-9 -9
0.13<em>m</em> = 14+0.09<em>m</em>
-0.09<em>m</em> -0.09<em>m</em>
0.04<em>m</em>= 14
14÷0.04= 350
<em>m</em>= 350
l o l
o k
s o
5x=x-9 and 4x-10y=8
lets graph that on desmos cause I'm too lazy to subsitute it .
it has one answer
Domain={-4,3} range={2,3}
Answer:
Initial Amount=1
Decay Factor=0.99987
Decay Rate=0.013%
Step-by-step explanation:
If P = 0.99987ᵃ
I. Initial amount
The initial amount is when a=0
P = 0.99987⁰ = 1
The Pressure at Sea Level=1
II. Decay factor
This is like the decay constant. From the model, P = 0.99987ᵃ, the decay constant/factor is 0.99987.
III. Decay Rate = 1-0.99987 = 0.00013
Expressed in Percentage = 0.013%
